Logical Effort of Complex Inverting Gates |
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| Logical effort of different complex gates, from Logical Effort book | |||||
| NAND gates' series N transistors | |||||
| 1 | 2 | 3 | 4 | ||
| NOR gates' series P transistors | 1 | 1.00 | 1.33 | 1.67 | 2.00 |
| 2 | 1.67 | 2.00 | 2.33 | 2.67 | |
| 3 | 2.33 | 2.67 | 3.00 | 3.33 | |
| 4 | 3.00 | 3.33 | 3.67 | 4.00 | |
From the analysis on NAND and NOR gates, we can extend the equation for
logical effort to the case of an arbitrary number of series N and P transistors.
A table of logical effort for all combinations of inverting complex gates from 1-4 series
transistors can be drawn up using Ohm's law and µ=2,
as in Logical Effort.
| Logical effort of different complex gates used in the vsclib | |||||
| NAND gates' series N transistors | |||||
| 1 | 2 | 3 | 4 | ||
| NOR gates' series P transistors | 1 | 0.98 | 1.20 | 1.41 | 1.61 |
| 2 | 1.55 | 1.77 | 1.99 | 2.21 | |
| 3 | 2.13 | 2.34 | 2.56 | 2.78 | |
| 4 | 2.70 | 2.92 | 3.13 | 3.35 | |
This can be compared with a table of logical effort used for the vsclib design.
The derivation of the numbers in this table is shown below.
In order to calculate the falling logical effort, the N transistors are
sized so that the conductivity of the series transistors is the same as a
single N transistor with a width of 1. For a complex gate with P:N transistor
ratio of γ this means that the equivalent inverter has a drive of
(P=γ,N=1), and the complex gate has
(P=KP·γ,N=KN).
Then the falling logical effort is
gd =
(KN+KP·γ)/(1+µ)
For the rising logical effort, we scale the P transistor of the equivalent inverter to
P=µ. The N transistor is then scaled by a factor of
µ/γ from this.
The series P transistor of the complex gate is then
KP× bigger than the equivalent inverter,
and the series N transistor is
KN× bigger. This gives a rising logical effort of
gu =
(KP·µ+KN·µ/γ)/(1+µ)
The logical effort g is then:
g =
½×(KP·γ+KN+KP·µ+KN·µ/γ)/(1+µ)
This is quite a useful result, as it is generic and applies as well to inverters, NAND and NOR gates.
The fastest gates can be found when
dg/dγ = 0 =
KP-KN·µ/γ2
from which
γ = √(KN·µ/KP)
for the fastest gates.
| Value of γ for the fastest versions of different complex gates | |||||
| NAND gates' series N transistors | |||||
| 1 | 2 | 3 | 4 | ||
| NOR gates' series P transistors | 1 | 1.50 | 1.94 | 2.29 | 2.60 |
| 2 | 1.10 | 1.41 | 1.67 | 1.90 | |
| 3 | 0.90 | 1.17 | 1.38 | 1.57 | |
| 4 | 0.79 | 1.02 | 1.20 | 1.36 | |
We use this expression to draw up a table of the γ values for the
fastest gates for all gates with up to 4 series P or N transistors. Our design
policy is to have a lower value of γ=2 and an upper value of γ=2.5
in order to keep the output rise and fall drive strengths reasonably balanced.
From this table, we can see that all gate types will have γ=2 except
for the 3-NAND and 4-NAND, which as we have already seen, will use values of
γ=2.33 and γ=2.5.
| Value of γ chosen for the different vsclib complex gates | |||||
| NAND gates' series N transistors | |||||
| 1 | 2 | 3 | 4 | ||
| NOR gates' series P transistors | 1 | 2 | 2 | 2.33 | 2.5 |
| 2 | 2 | 2 | 2 | 2 | |
| 3 | 2 | 2 | 2 | 2 | |
| 4 | 2 | 2 | 2 | 2 | |
Now for each gate type, we have values of P:N transistor ratio (γ),
P and N transistor conductivity coefficients
(KP,KN),
and a value for mobility µ=2.25. Thus for each gate type
we can calculate the logical effort
g =
½×(KP·γ+KN+KP·µ+KN·µ/γ)/(1+µ).
This gives us the table at the top of the page,
showing logical effort for all 16 inverting gate types with 1-4 series transistors.
| Logical effort of different complex gates used in the vsclib | |||||||
| NAND gates' series N transistors | |||||||
| 1 | 2 | 3 | 4 | NN | |||
| 3/3 | 5/3 | 7/3 | 9/3 | KN | |||
| NOR gates' series P transistors | 1 | 8/8 | 0.98 | 1.20 | 1.41 | 1.61 | |
| 2 | 15/8 | 1.55 | 1.77 | 1.99 | 2.21 | ||
| 3 | 22/8 | 2.13 | 2.34 | 2.56 | 2.78 | ||
| 4 | 29/8 | 2.70 | 2.92 | 3.13 | 3.35 | ||
| NP | KP | g = ½×(KP·γ+KN+KP·µ+KN·µ/γ)/(1+µ) | |||||